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  1. #include <stdio.h>
  2. //a{n} = -6a{n-1} -9a{n-2}, a{1}=1, a{2}=2(再帰あり版)
  3. int rec(int n){
  4. 	if(n==1){
  5. 		return 1;
  6. 	}
  7. 	else if(n==2){
  8. 		return 2;
  9. 	}
  10. 	else{
  11. 		return -6*rec(n-1)-9*rec(n-2);
  12. 	}
  13.  
  14. }
  15.  
  16. int main(void) {
  17.     int n = 4;
  18.     printf("数列a%dの値は%d\n", n, rec(n));
  19. 	return 0;
  20. }
  21.  
  22.  
Success #stdin #stdout 0s 5308KB
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Standard input is empty
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数列a2の値は2
https://ideone.com/N5b2gh
第5回　3項間漸化式
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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