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  1. def ne(i,j):
  2. 	s = i + j
  3. 	if s>3:
  4. 		return 6-s
  5. 	return s
  6. def task(n,i,j):
  7. 	if n == 1:
  8. 		print("(",i,",",j,")",end="")
  9. 		return()
  10. 		return(task(n-1,i,ne(i,j))+task(1,i,j)+task(n-1,ne(i,j),j))
  11.  
  12. task(3,1,3)
Success #stdin #stdout 0.07s 14032KB
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https://ideone.com/QDnpQw
language:
Python 3 (python  3.12)
created:
2 days ago
visibility:
public

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