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  1. #include <stdio.h>
  2. int sum(int x,int y){
  3.     return x+y;
  4. }
  5.  
  6. int jijou(int x){
  7.     return x*x*x;
  8. }
  9.  
  10. int main(void) {
  11.     int a,b;
  12.     a=2;
  13.     b=-3;
  14.     printf("(%d+%d)^3=%d\n",a,b,jijou(sum(a,b)));
  15. 	return 0;
  16. }
  17.  
Success #stdin #stdout 0s 5300KB
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Standard input is empty
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(2+-3)^3=-1
https://ideone.com/YPCov0
language:
C (gcc 8.3)
created:
5 days ago
visibility:
public

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