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  1. #include <stdio.h>
  2. //正の奇数nを引数とし，以下の正の奇数の和を求める関数
  3. int rec(int n){
  4.     if (n == 1){
  5.         return 1;
  6.     }
  7.     else{
  8.         return rec(n-2)+n;
  9.     }
  10. }
  11. int main(void) {
  12.     int n ;
  13.     for(n=1;n<=9;n+=2){
  14.     printf("%d以下の正の奇数の和は%d\n", n, rec(n));
  15.     }
  16. 	return 0;
  17. }
Success #stdin #stdout 0s 5328KB
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Standard input is empty
stdout
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1以下の正の奇数の和は1
3以下の正の奇数の和は4
5以下の正の奇数の和は9
7以下の正の奇数の和は16
9以下の正の奇数の和は25
https://ideone.com/ZGY8H0
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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