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  1. #include <stdio.h>
  2. //正の奇数nを引数とし，以下の正の奇数の和を求める関数
  3. int rec(int n){
  4.     if (n== 1){
  5.         return 1;
  6.     }
  7.     else{ 
  8.     	return n+rec(n-2);
  9.  
  10.     }
  11. }
  12. int main(void) {
  13.     int n = 11;
  14.     printf("%d以下の正の奇数の和は%d\n", n, rec(n));
  15. 	return 0;
  16. }
Success #stdin #stdout 0s 5280KB
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11以下の正の奇数の和は36
https://ideone.com/ZyBH2R
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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