#include <bits/stdc++.h>
using namespace std;
#define int long long int
#define double long double
#define print(a) for(auto x : a) cout << x << " "; cout << endl
const int M = 1000000007;
const int N = 3e5+9;
const int INF = 2e9+1;
const int LINF = 2000000000000000001;
inline int power(int a, int b, int mod=M) {
int x = 1;
a %= mod;
while (b) {
if (b & 1) x = (x * a) % mod;
a = (a * a) % mod;
b >>= 1;
}
return x;
}
//_ ***************************** START Below *******************************
//* Case 2 : n <= 1e9 && r <= 20
//* With Modulo :
//* TC = O(r + logM) SC = O(1)
int nCr(int n, int r){
if(r>n || r<0) return 0;
if(r>n-r) r = n-r; //* optimization nCr == nCn-r
int res = 1;
for(int i=1; i<=r; i++){
res = (res * (n-i+1)) % M;
}
int rFact = 1;
for(int i=1; i<=r; i++){
rFact = (rFact * i)%M;
}
res = (res%M * power(rFact, M-2, M) ) % M;
return res;
}
//* Without Modulo :
//* TC = O(r) , SC = O(1)
int nCr2(int n, int r){
if(r>n || r<0) return 0;
if(r>n-r) r = n-r; //* optimization nCr == nCn-r
int res = 1;
for(int i = 1; i <= r; i++){
res = (res * (n - i + 1)) / i;
}
return res;
}
//* recursive
//* TC = O(rLogM) SC = O(r)
int nCr3(int n, int r, int M) {
if (r > n || r < 0) return 0;
if (r == 0) return 1;
if (r > n - r) r = n - r;
int res = (n * nCr3(n-1,r-1, M) ) % M;
res = (res * power(r, M - 2, M)) % M;
return res;
}
int consistency(int n, int r){
return nCr(n, r);
}
int practice(int n, int r){
return 0;
}
void solve() {
int n, r;
cin>> n >> r;
cout << consistency(n, r) << endl;
}
int32_t main() {
ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
int t = 1;
cin >> t;
while (t--) {
solve();
}
return 0;
}
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