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  1. #include <stdio.h>
  2. //再帰を用いて1からnまでの二乗和1^2 + 2^2 + 3^2 + ... + n^2を計算する
  3.  
  4. int main(void) {
  5.     int n,an;
  6. 	n=4;
  7.     for(int i=1;i<=n;i++){
  8.     an=an+i*i;
  9. 	printf("1から%dまでの二乗和の値は%d\n",i,an);
  10.  
  11.   }
  12. }
  13.  
Success #stdin #stdout 0s 5320KB
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stdin
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Standard input is empty
stdout
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1から1までの二乗和の値は-276094591
1から2までの二乗和の値は-276094587
1から3までの二乗和の値は-276094578
1から4までの二乗和の値は-276094562
https://ideone.com/jCgUNl
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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