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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4.  
  5. 	int n,x[1000];
  6. 	x[0] = 1;
  7.  
  8.     for(n = 0;n < 1000;n ++){
  9.     	if((x[n+1] = 2 * x[n] + 1) >= 1000){
  10.     		printf("この数列が初めて１０００を超えたときのnの値は%dです。\n",n+2);
  11.     		break;
  12.     	}
  13.     }
  14.  
  15. 	return 0;
  16. }
  17.  
Success #stdin #stdout 0s 5316KB
comments (?)
stdin 
Standard input is empty
stdout 
この数列が初めて１０００を超えたときのnの値は10です。
https://ideone.com/kdpGBg
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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