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  1. #include <bits/stdc++.h>
  2. using namespace std;
  3.  
  4. int main() 
  5. {
  6.     // index     1   2  3   4  5
  7.      int b[5] = {5,-3,-5,15,5};
  8.      int n=5;
  9.  
  10.     int maxPrefixSum[5];
  11.     int maxSuffixSum[5];
  12.  
  13.     // current = 0
  14.     // maxPrefixSum = 0
  15.     //Initially both the current and maxPrefixSum will be zero 
  16.     //     5     =  max( 5 ,  0   +   5)
  17.     //  current = max(b[i] , current + b[i])
  18.     //               5         = max(  5    ,     5 )
  19.     //maxPrefixSum[i] = max(maxPrefixSum[i-1] , current)
  20.  
  21.     int current = b[0];
  22.     maxPrefixSum[0] = b[0];
  23.     for(int i=1; i<n; i++)
  24.     {
  25.         current = max(b[i] , current + b[i]);
  26.         maxPrefixSum[i] = max(maxPrefixSum[i-1] , current);
  27.     }
  28.  
  29.     // current = 0
  30.     //maxSuffixSum = 0
  31.     //     15  =    max( 15,       0  +  15)
  32.     //current = max(b[i] , current + b[i]);
  33.     //           20                = max(   15+5  ,  15)
  34.     //maxSuffixSum[i] = max(maxSuffixSum[i+1] , current);
  35.     current = b[n-1];
  36.     maxSuffixSum[n-1] = b[n-1];
  37.     for(int i=n-2; i>=0; i--)
  38.     {
  39.         current = max(b[i] , current + b[i]);
  40.         maxSuffixSum[i] = max(maxSuffixSum[i+1] , current);
  41.     }
  42.  
  43.  
  44.     int maxSum = INT_MIN;
  45.     for(int i=1; i<n-1; i++)
  46.     {
  47.         //     25        = max(     0          ,        5                     +           20)
  48.         maxSum = max(maxSum , maxPrefixSum[i] + maxSuffixSum[i+1]);
  49.     }
  50.  
  51.     cout<<"Max sum of two nonoverlapping subarrays: "<<maxSum; // o/p -> 25
  52. }
Success #stdin #stdout 0.01s 5296KB
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stdin
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Standard input is empty
stdout
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Max sum of two nonoverlapping subarrays: 25
https://ideone.com/ur3X12
language:
C++ (gcc 8.3)
created:
2 days ago
visibility:
public

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